160+36x+2x^2=2x

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Solution for 160+36x+2x^2=2x equation: 



160+36x+2x^2=2x

We move all terms to the left:

160+36x+2x^2-(2x)=0

We add all the numbers together, and all the variables

2x^2+34x+160=0

a = 2; b = 34; c = +160;
Δ = b2-4ac
Δ = 342-4·2·160
Δ = -124
Delta is less than zero, so there is no solution for the equation

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